delta V. in. Heisenberg questions

[SarahCoufal_1k]

In 1.B.27,the question says: a bowling ball of 8 .00kg is being rolled down an alley lane at 5.00 +/- 5.0 m/s. what is the minimum uncertainty in its position?

For uncertainty in velocity (delta v), would it be 10 or 5? I thought it would be 10. because the range is from 0-10, however the solutions book seems to be using 5.

[Ada Chung 1C]

The uncertainty in velocity would be 10 in this case because it is vfinal-vinitial. I'm assuming there's a typo in the solutions manual?

[SajaZidan_1K]

This is a typo: On the website you can find the typo and the correction: "1B.27
Solution manual states Δv = 5.0 m.s-1
Velocity was given as 5.00 ± 5.0 m.s-1
Therefore Δv = 10.0 m.s-1
With the correction, the final answer is: Δx = 6.7 x 10-37 m"

[Asia Yamada 2B]

I agree that the uncertainty in velocity would be 10 because you multiply by two when there’s a ± because that represents the range of values that the speed could be. I believe that there’s an error in the answer key. You can find the correct solution here. https://lavelle.chem.ucla.edu/wp-content/supporting-files/Chem14A/Solution_Manual_Errors_7Ed.pdf

[Breanna Ouyang 1I]

Yep it's 10 and not 5! There was an earlier post or correction clarifying that the solutions manual has the wrong answer

[Nan_Guan_1L]

yeah it's 10 not 5. I googled this question and found a 2017 post on chemistry community where Chem_Adm confirmed this. There's also a section on Dr.Lavelle's website that includes all the textbook corrections. You can also refer to that! Hope this helps!

[505612629]

The uncertainty in velocity is the range since its 5 and the uncertainty is +/-5, You would add 5+5=10 minus 5-5=0. 10-0=10, so your deltaV is 10.