Heisenberg's Indeterminacy Equation


Moderators: Chem_Mod, Chem_Admin

Selina
Posts: 12
Joined: Fri Sep 25, 2015 3:00 am

Heisenberg's Indeterminacy Equation

Postby Selina » Sun Oct 11, 2015 6:05 pm

Hi, I'm just still confused about how this equation can be used?

Thanks!

PaigeBlack
Posts: 32
Joined: Fri Sep 25, 2015 3:00 am

Re: Heisenberg's Indeterminacy Equation

Postby PaigeBlack » Sun Oct 11, 2015 6:50 pm

This equation is simply used to determine the amount of uncertainty which is present when calculating either the position or momentum of an electron.

Jacob Afable 3J
Posts: 41
Joined: Fri Sep 25, 2015 3:00 am

Re: Heisenberg's Indeterminacy Equation

Postby Jacob Afable 3J » Tue Nov 24, 2015 12:48 am

The question could also ask the minimum uncertainty in velocity. For Heisenberg's uncertainty principle, be careful to notice what information is given. For cases where they give the radius size of an certain metal atom, make sure to double the length of the radius to get the diameter, which represents x. I suggest writing down what is given first and then write down the equation.

904634956
Posts: 5
Joined: Fri Jun 17, 2016 11:28 am

Re: Heisenberg's Indeterminacy Equation

Postby 904634956 » Sun Jul 10, 2016 11:46 pm

I am still a bit confused when inputting the given velocity into the equation. What I understand is if you are given something like 51 +/- 0.80, you would just use the .80 part for delta v. Somewhere in the book, there is an example like this, but they say to multiply by 2. So from this, would I just multiply .80*2? and then input that as my result? If so, why do we have to do this? I was thinking since , but I'm still a bit confused on this part.

Chem_Mod
Posts: 18400
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 435 times

Re: Heisenberg's Indeterminacy Equation

Postby Chem_Mod » Mon Jul 11, 2016 10:34 am

Multiplying by two will yield same result from doing the subtraction of max minus min of the speed range given.


Return to “Heisenberg Indeterminacy (Uncertainty) Equation”

Who is online

Users browsing this forum: No registered users and 1 guest