## Module Post-Assessment

$\Delta p \Delta x\geq \frac{h}{4\pi }$

KMcFarland_2L
Posts: 95
Joined: Wed Sep 30, 2020 9:52 pm

### Module Post-Assessment

How does the precision of the position affect the precision of the momentum, and vice versa? For example, if the position determined is more precise, will that make the momentum determined less precise or more precise?

Samantha Pedersen 2K
Posts: 133
Joined: Wed Sep 18, 2019 12:21 am
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### Re: Module Post-Assessment

If the position determined is more precise, then the momentum determined will be less precise. If the momentum determined is more precise, then the position determined will be less precise. This is due to the Heisenberg Uncertainty Principle: the product of the uncertainty in position and the uncertainty in momentum must be greater than or equal to h/(4*pi). Therefore, if the uncertainty in position decreases, then the uncertainty in momentum must increase in order to meet the condition. I hope this helps!