## delta x for textbook question 1b 27

$\Delta p \Delta x\geq \frac{h}{4\pi }$

Kelly Yun 3K
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Joined: Wed Sep 30, 2020 10:03 pm

### delta x for textbook question 1b 27

According to the question, a bowling ball of mass 8.00 kg is rolled down a bowling alley lane at 5.00+-5.0m/s, then since the position is + or - 5 from 5, isn't the spread/delta x 10.0? The solution manual used 5.0 so I was confused because I thought that delta x was the spread of uncertainty (2x the value being + or - from the measurement).

Posts: 44
Joined: Wed Sep 30, 2020 10:03 pm

### Re: delta x for textbook question 1b 27

This is an error in the textbook. The real answer uses 10, which you're right about! You can find the corrections on the solution errors page on his website.

Khushi_Gupta_2B
Posts: 30
Joined: Wed Sep 30, 2020 9:45 pm

### Re: delta x for textbook question 1b 27

I'm not sure if you meant delta-V and wrote delta-X by mistake, but just to clarify this question is asking us to find the minimum uncertainty which is delta X. The two values given in the question tell us the mass and velocity of the bowling ball. Since the velocity is 5± 5m/s delta-V would be 10, not delta-X.