1B.27

[KaylynnPierce2I]

I'm a bit confused by 1B.27; I inputted 10 for the value of delta v since with 5.00±5 , (5−5=0) and (5+5=10) and (10−0=10). But my answer was still not correct. But when I use 5 for delta v, my answer is correct. I'm just wondering if I'm misinterpreting the value of delta v?
Question: 1B.27 A bowling ball of mass 8.00 kg is rolled down a bowling alley lane at 5.00± 5ms^(−1). What is the minimum uncertainty in its position?

[Jaylin Hsu 1C]

Hi, so the minimum uncertainty in position can be calculated using the principle: uncertainty in momentum times uncertainty in position is greater than or equal to h/4pi. Momentum, in this problem, can be viewed as the uncertainty in velocity times the mass. The mass is 8.00 kg and the uncertainty in velocity is 10. So you would multiply these two values. Then, do (h/4pi) divided by the product you got. This would result in the uncertainty in position.

[Alyssa Ly 2G]

Hello!

For question 1B.27, the way you did the problem initially is correct! The value that you plug in for the uncertainty in velocity is definitely supposed to be 10. The answer given in the textbook for this problem was actually wrong. You can check the Solutions Manual Error and it should show you the correct answer, which is what you should have gotten when you used 10!

I hope this helped! :)))