Module #17

[205696437]

I confused on this question "calculate the uncertainty in the position of an electron if its uncertainty in speed is one hundredth the speed of light?

[Maleeha Zaman 1K]

Hi, you must use the Heisenberg Uncertainty Equation to solve this problem. For the velocity, you going to divide the speed of light (3x10^8) by 100, and you should get 3x10^6 as your new velocity. Then just rearrange the equation and plug in the numbers to solve for the uncertainty of position or change in x.

[Jennifer Huynh 3I]

Use the uncertainty equation ∆p∆x ≥ h/(4pi) to solve this problem. First, find the uncertainty in speed using the given information by dividing 3.00x10^8 by 100 to get ∆v = 3.00x10^6. We know that momentum is equal to mass times velocity, so ∆p = (mass of an electron)*∆v = 2.73x10^-24. Next, we can isolate ∆x: ∆x ≥ h/(4pi*∆p), and using the calculated values we obtained, we can find ∆x, the uncertainty in the position of the electron.

[Acharya Ranawat 3E]

In this question you would need to use the fact that delta p is equal to delta v times mass. Hence, the uncertainty in velocity would be 3x10^6 m/s. Then you would just find delta x by plugging it into the Heisenberg Uncertainty equation.

[Joelle Tran 1K]

Hey!

For this problem I got the delta v by doing .01*(3 E8 m/s) = 3 E6 m/s. Then, I plugged that value into my delta p = m*delta v equation with m being 9.11 E-31 kg and got delta p = 2.7 E-24 kg*m/s.