2.31 asks which of the following subshells cannot exist in an atom: (a) 2d cannot exist (b) 4d exists (c) 4g cannot exist (d) 6f exists
First off, I don't really understand this.
Second, for c, does a g orbital even exist??
okay that's all thank you
HW 2.31 [ENDORSED]
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Re: HW 2.31 [ENDORSED]
the subshells 2d and 4g do not exist because there is not an element to be assigned to in that subshell. The d-block of subshells is for transition metals and begin at 3d. The 4g could simply not be possible because the subshells on the periodic table go up to the f-block. The 4d and 6f subshells can exist because they are in the range of the periodic table and can be assigned to an element.
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Re: HW 2.31
2d does not exist because the first subshell for d is 3d and there is no such thing as a g orbital.
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Re: HW 2.31
the d orbitals start at 3 so a 2d orbital cannot exist, further the g orbital is not an orbital that one cannot be true either
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Re: HW 2.31
Since subshells correspond to the layout of the periodic table, did the development of both occur during the same time period?
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Re: HW 2.31
okay I get it now, so this might be a really silly follow up and I don't know if this will make sense but stick with me here lol
so the f block, extends out from the d block right? So if d starts at n= 3 (like 3d¹⁰), does f start at n= 5 and can either be 5f or 6f?
so the f block, extends out from the d block right? So if d starts at n= 3 (like 3d¹⁰), does f start at n= 5 and can either be 5f or 6f?
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