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Posted: Sun Apr 29, 2018 8:59 pm
by alexagreco1A
Write the subshell notation and the number of orbitals having the following quantum numbers:

When it asks for the number of orbitals, is that the same as asking for the number of subshells? If not, how do you solve for this?

Re: 2.27

Posted: Sun Apr 29, 2018 9:24 pm
by ramayyala1G
Orbitals and subshell are not the same thing. It is asking you to find the number of orbitals within the subshell. So lets look at (a). it gives you n= 5 and l=2. If n=5 you know it is on the 5th energy level and l=2 means that is it on the d-block hence 5d is the subshell notation. We know l=2 correlates to the d-block because l=1 is the s-block and l=0 is the p-block. In order to find the number of orbitals, the easiest thing to do is understand that the d-block as 10 electrons meaning that it will have 5 orbitals. Just count the number of elements on the period table in one row of the d block. There is 10 elements meaning that there is 10 electrons to fill in the d-block. Divide the 10/2 to get 5 orbitals.

Re: 2.27

Posted: Sun Apr 29, 2018 9:33 pm
by victoriatanaka1C
Orbitals and subshells are not the same thing!

Shells are determined by the value of n.

Subshells are determined by the value of l (which can go from 0 to the value of n-1).

Orbitals are determined by the value of m (which are valued between l and -l).

So if you're given n = 4 and l = 1, m can be 1, 0 or -1.

Re: 2.27  [ENDORSED]

Posted: Mon May 07, 2018 3:14 pm
by Chem_Mod
I just want to correct a portion of Ramay's response. l=0 is the s orbital and l=1 is the p orbital.

Re: 2.27

Posted: Fri Oct 19, 2018 12:22 am
by Katie_Duong_1D
In sub shell notation, n refers to the coefficient.

For example,

a. n = 5, l = 2 would be 5d. This is because n=5, so the coefficient would be 5, and l = 2 corresponds with d. There are 5 possible electrons with that quantum number because l=2, so the possible electrons would be -l and +1 (-2, -1, 0, 1, 2)