HELP hw problem 2.17  [ENDORSED]

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april_bussey_1C
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HELP hw problem 2.17

Postby april_bussey_1C » Sun Apr 29, 2018 10:42 pm

2.17 How many orbitals are in subshells with l equal to (a) 0; (b) 2; (c) 1; (d) 3?

I saw a previous response for this question and i'm not fully understanding the concept. i know that when l=0, m must equal 0.... but how do we know that when l=2 it'll have 5 orbitals?? can someone please help me unpack this problem

Miya Lopez 1I
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Re: HELP hw problem 2.17

Postby Miya Lopez 1I » Sun Apr 29, 2018 11:07 pm

When l=2, m can be -2, -1, 0, 1, 2 which corresponds to 5 orbitals.

I got this from the chart we wrote in lecture on 4/25.

Hope this helps :)

Maria Roman 1A
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Joined: Fri Apr 06, 2018 11:04 am

Re: HELP hw problem 2.17

Postby Maria Roman 1A » Sun Apr 29, 2018 11:11 pm

Figure 2.3 in the textbook can help with this. at L=0, for example, there is one orbital.

804991762_4A
Posts: 47
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Re: HELP hw problem 2.17

Postby 804991762_4A » Sun Apr 29, 2018 11:14 pm

Miya Lopez 1L wrote:When l=2, m can be -2, -1, 0, 1, 2 which corresponds to 5 orbitals.

I got this from the chart we wrote in lecture on 4/25.

Hope this helps :)


Hi, how did you get (-2,-1,0,1,2) from just l=2?

Rebekah Kaufman 1L
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Re: HELP hw problem 2.17  [ENDORSED]

Postby Rebekah Kaufman 1L » Sun Apr 29, 2018 11:31 pm

You can get (-2,-1,0,1,2) from l=2 because as the textbook says, "There are 2l +1 different values of m for a given value of l." This means that when l=2 there will be a total of 5 possible m values. We also learned that m=l,l-1,...-l. This basically means that m can be +l and -l and every whole number in between those two values.

april_bussey_1C
Posts: 30
Joined: Fri Apr 06, 2018 11:02 am

Re: HELP hw problem 2.17

Postby april_bussey_1C » Sun Apr 29, 2018 11:51 pm

okay yay I actually understand now! Thank you guys!!!!


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