Explanation to the answer of the question 2.31

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Kalsuda Lapborisuth 1B
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Joined: Fri Apr 06, 2018 11:03 am

Explanation to the answer of the question 2.31

Postby Kalsuda Lapborisuth 1B » Sun Apr 29, 2018 11:26 pm

The question asks "Which of the following subshells cannot exist in an atom: (a) 2d; (b) 4d; (c) 4g; (d) 6f?". I understand that a and c cannot exist but I am not sure about the explanation as to why b and d can exist.

Maria Roman 1A
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Joined: Fri Apr 06, 2018 11:04 am

Re: Explanation to the answer of the question 2.31

Postby Maria Roman 1A » Sun Apr 29, 2018 11:31 pm

I believe there is no such thing as an orbital g

Haison Nguyen 1I
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Re: Explanation to the answer of the question 2.31

Postby Haison Nguyen 1I » Mon Apr 30, 2018 5:26 pm

6f would consist of the lanthanoids and 4d would be the row where yttrium starts and cadmium ends (when n = 5).

Joanna Pham - 2D
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Joined: Fri Apr 06, 2018 11:04 am

Re: Explanation to the answer of the question 2.31

Postby Joanna Pham - 2D » Thu May 03, 2018 9:38 am

I’m confused as to why 4g can’t exist. Can someone explain this to me please?

Celeste Martinez 1K
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Re: Explanation to the answer of the question 2.31

Postby Celeste Martinez 1K » Thu May 03, 2018 3:28 pm

I had the same question as to why 2d does not exist if 2s and 2p exist. Why does it stop at 2p and not continue?


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