2.17

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Jade Corpus-Sapida 1G
Posts: 35
Joined: Fri Apr 06, 2018 11:02 am

2.17

Postby Jade Corpus-Sapida 1G » Tue May 01, 2018 1:19 pm

In this problem we are given the l value, so then I solved for what n (energy level) is (l= n-1), but then I'm confused as to how the answers are
a) 1 orbital
b) 5 orbitals
c) 3 orbitals
d) 7 orbitals

does the value of n just relate to the different shapes?

AnnaYan_1l
Posts: 96
Joined: Fri Apr 06, 2018 11:05 am
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Re: 2.17

Postby AnnaYan_1l » Tue May 01, 2018 2:00 pm

The question is referring to ml, so:

For part a, when l = 0 (it is an s orbital), there is only one possible value for ml (which is 0), so the answer is 1.

When l = 2, this means ml can be: -2, -1, 0, 1, 2 (5 values)

When l = 1, this means that ml can be: -1, 0, 1 (3 values)

When l = 3, this means that ml can be: -3, -2, -1, 0, 1, 2, 3 (7 values)

Does this clarify everything? I hope this helps!

Jade Corpus-Sapida 1G
Posts: 35
Joined: Fri Apr 06, 2018 11:02 am

Re: 2.17

Postby Jade Corpus-Sapida 1G » Tue May 01, 2018 3:06 pm

okay, its starting to make sense now. However is the pattern always going to be l, l-1, -l? So it goes in both positive and negative directions?

Alma Flores 1D
Posts: 64
Joined: Wed Nov 08, 2017 3:01 am

Re: 2.17

Postby Alma Flores 1D » Tue May 01, 2018 3:15 pm

Yes, the pattern for mI will always be -I to +I. Count the values to get the number of orbitals.

Jade Corpus-Sapida 1G
Posts: 35
Joined: Fri Apr 06, 2018 11:02 am

Re: 2.17

Postby Jade Corpus-Sapida 1G » Tue May 01, 2018 3:52 pm

okay thanks for the help!


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