Shielding  [ENDORSED]

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Michael Nirula
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Shielding

Postby Michael Nirula » Fri Oct 19, 2018 10:19 pm

Because the 2S and 2P orbitals both have the quantum # n=2, I thought that these orbitals were the same distance from the nucleus, but I believe Prof. Lavelle mentioned today that the 2P orbital experiences shielding from the 2S orbital. Is this true/does the 2P orbital experience shielding from the 2S orbital?

Swetha Ampabathina1I
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Re: Shielding

Postby Swetha Ampabathina1I » Fri Oct 19, 2018 10:36 pm

Yes the 2p orbital does experience shielding from the 2s orbital since the 2s orbital is closer to the nucleus and can block out the charge from the electrons from the 2p orbital since they are farther away

Hannah Yates 1K
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Re: Shielding

Postby Hannah Yates 1K » Sat Oct 20, 2018 1:32 pm

Technically the 2s and 2p are the same orbital, but they have different suborbital. S is the closest suborbital to the nucleus, then P, then D, and so on.

Madeline Motamedi 4I
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Joined: Fri Sep 28, 2018 12:23 am

Re: Shielding

Postby Madeline Motamedi 4I » Sat Oct 20, 2018 2:37 pm

So, from what I'm understanding from this, the sub orbitals within one n are different distances from the nucleus. Am I correct?

Andrew Lam 3B
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Re: Shielding

Postby Andrew Lam 3B » Sat Oct 20, 2018 2:39 pm

The p-orbital experiences less pull from the nucleus because some of the repulsion from s-orbital electrons are also affecting it. Thus, we need something called effective nuclear charge to describe the binding strength of electrons. They are the same energy level (in the case of 2s and 2p) but are varying distances from the nucleus.

Jonathan Pai 2I
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Re: Shielding  [ENDORSED]

Postby Jonathan Pai 2I » Sat Oct 20, 2018 5:33 pm

The terms are subshell and orbital, not suborbital. shell(n)>>subshell(l)>>>orbital(ml)

Yes you are correct. The n value, for example 2 in 2s and 2p, provides a small "range" of energy levels. In that range of n=2, s orbital is closer than p orbital, so the p orbital does experience less attraction b/c the s orbital is closer. So even though they are at the same energy level of n=2, the s is closer within that energy level(range).

Margaret Akey
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Re: Shielding

Postby Margaret Akey » Sat Oct 20, 2018 7:28 pm

So the orbitals closer to the nucleus are always the ones that shield the further away electrons?

Josceline 3J
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Joined: Fri Sep 28, 2018 12:21 am

Re: Shielding

Postby Josceline 3J » Sat Oct 20, 2018 9:56 pm

Hello everyone, I'm struggling a bit with this concept. In the hw, it told us to find the ground state of elements (ex: Bi which has 83 electrons) and then the answer was [Xe]4f^(14)5d^(10)6s^(2)6p^(3). When it comes to elements with a high number of electrons is there another way to go about this other than having to do the (s,p,d,f) level one by one to come to the answer. It can be a lot of work when dealing with big numbers.

danicatran4
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Joined: Fri Sep 28, 2018 12:17 am

Re: Shielding

Postby danicatran4 » Sun Oct 21, 2018 4:43 pm

What are the consequences of shielding? I understand it means the electrons far away from the nucleus are less electronegative, but why does it matter?

Venya Vaddi 1L
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Re: Shielding

Postby Venya Vaddi 1L » Sun Oct 21, 2018 4:50 pm

Because of shielding, the outer electrons feel reduced electrostatic attraction, resulting in an effective nuclear charge. Shielding explains why it is easier (in other words, requires less energy) to remove the outer electrons because the outer electrons have less of an electrostatic attraction from the nucleus. Shielding is also an argument used to explain other periodic trends.

Michael Nirula
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Joined: Fri Sep 28, 2018 12:27 am

Re: Shielding

Postby Michael Nirula » Sun Oct 21, 2018 7:12 pm

Ok great think I've got it thanks guys

Brian Chang 2H
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Joined: Fri Sep 28, 2018 12:17 am

Re: Shielding

Postby Brian Chang 2H » Mon Oct 22, 2018 11:14 am

The 2s orbital shields the 2p orbitals from the electronegative attraction of the nucleus.

Mayaal_Khan_4H
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Joined: Fri Sep 28, 2018 12:28 am

Re: Shielding

Postby Mayaal_Khan_4H » Mon Oct 22, 2018 12:36 pm

Josceline 3J wrote:Hello everyone, I'm struggling a bit with this concept. In the hw, it told us to find the ground state of elements (ex: Bi which has 83 electrons) and then the answer was [Xe]4f^(14)5d^(10)6s^(2)6p^(3). When it comes to elements with a high number of electrons is there another way to go about this other than having to do the (s,p,d,f) level one by one to come to the answer. It can be a lot of work when dealing with big numbers.


Starting with the Nobel gas to make your answer shorter is the only way, I think.

Brian Chang 2H
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Joined: Fri Sep 28, 2018 12:17 am

Re: Shielding

Postby Brian Chang 2H » Mon Nov 05, 2018 1:56 pm

Josceline 3J wrote:Hello everyone, I'm struggling a bit with this concept. In the hw, it told us to find the ground state of elements (ex: Bi which has 83 electrons) and then the answer was [Xe]4f^(14)5d^(10)6s^(2)6p^(3). When it comes to elements with a high number of electrons is there another way to go about this other than having to do the (s,p,d,f) level one by one to come to the answer. It can be a lot of work when dealing with big numbers.


Start from the closest Noble gas (lower in electron number, not higher. lol.) and work upwards. There is no short notation for this.

Shibhon_Shepard
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Joined: Wed Nov 15, 2017 3:04 am

Re: Shielding

Postby Shibhon_Shepard » Sat Nov 10, 2018 6:36 pm

WHAT DOES THIS EVEN MEAN????? I don't even remember this being talked about.


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