## Homework Ch.2 Question 15, 6th Edition

VGonzalez
Posts: 30
Joined: Fri Sep 28, 2018 12:18 am

### Homework Ch.2 Question 15, 6th Edition

How many (a) nodal planes, (b) radial nodes are there in a 3p-orbital?

Is there a way to tell how many nodal planes and radial nodes there are based on an electron state?

AustinGrove3B
Posts: 53
Joined: Fri Sep 28, 2018 12:23 am

### Re: Homework Ch.2 Question 15, 6th Edition

I think there would be 1 nodal plane in each p orbital. There are 3 orbitals in the p-block, so technically there would be 3 total nodal planes- 1 in each orbital.

Matthew Tran 1H
Posts: 165
Joined: Fri Sep 28, 2018 12:16 am

### Re: Homework Ch.2 Question 15, 6th Edition

I think the more important concept would be that simplest s-orbitals have 0 nodal planes, p-orbitals have 1, d-orbitals have 2, and f-orbitals have three. This is the answer given in the solutions manual.

Sophia Ding 1B
Posts: 62
Joined: Fri Sep 28, 2018 12:16 am

### Re: Homework Ch.2 Question 15, 6th Edition

The number of nodal planes is equal to the value of l. So for 3p, l =1, thus there would only be one nodal plane.

Celine Hoh 2L
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

### Re: Homework Ch.2 Question 15, 6th Edition

The answer given in the solution manual is
a) 1 nodal plane

Celine Hoh 2L
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

### Re: Homework Ch.2 Question 15, 6th Edition

But the textbook says that

= n-1-l
Which should give us
=3-1-1
=1

Celine Hoh 2L
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

### Re: Homework Ch.2 Question 15, 6th Edition

605122791 wrote:But the textbook says that

= n-1-l
Which should give us
=3-1-1
=1