Heisenberg

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Claudia Luong 4K
Posts: 59
Joined: Fri Sep 28, 2018 12:25 am

Heisenberg

Postby Claudia Luong 4K » Sun Oct 28, 2018 10:47 pm

I have trouble understanding how to apply Heisenberg's uncertainty principle. Just to confirm, if the problem states, for example, that the speed is known to be +/- 0.55 m/s then the change in velocity that we plug into the equation would be 2(0.55) and not 0.55 right?

604656370
Posts: 30
Joined: Fri Sep 28, 2018 12:25 am

Re: Heisenberg

Postby 604656370 » Sun Oct 28, 2018 11:12 pm

Yes, that is correct! The uncertainty in velocity is the aggregate unknown velocity. For instance, if the velocity is stated to be 1 m/s +/- 0.55 m/s then the velocity could be between 0.45 m/s and 1.55 m/s. Thus, the uncertainty would be 1.55 - 0.45 = 1.10 m/s (or 2 X 0.55).

daniela3D
Posts: 19
Joined: Fri Sep 28, 2018 12:25 am

Re: Heisenberg

Postby daniela3D » Mon Oct 29, 2018 11:51 pm

Correct! Each time you see +/-, multiply the number given by 2.


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