2.25 6th Edition

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Dustin Shin 2I
Posts: 64
Joined: Fri Sep 28, 2018 12:26 am

2.25 6th Edition

Postby Dustin Shin 2I » Sun Oct 28, 2018 11:59 pm

Hello, the question asks for the number of electrons in an orbital. Since the maximum number fo electrons in increasing orbital order is 2 , 4, 10, 14 , etc., do we count the orbitals in just the orbital or the ones before it as well?

katherinemurk 2B
Posts: 68
Joined: Wed Nov 15, 2017 3:02 am

Re: 2.25 6th Edition

Postby katherinemurk 2B » Mon Oct 29, 2018 12:21 am

For this question you just take the number of orbitals and multiply by 2 to get the number of electrons that can occupy that specific orbital. So for example the 4p orbital corresponds to the angular momentum quantum number 1. This number can have 3 values of the magnetic quantum number -1,0,1. Thsi means there are 3 orbitals. 3 times 2 is 6, so 6 electrons can occupy that orbital.

Grace Kim 1J
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am
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Re: 2.25 6th Edition

Postby Grace Kim 1J » Tue Oct 30, 2018 4:18 pm

Personally, the best way to approach this problem is to remember these key points:
s orbital; l=0
p orbital; l=1
d orbital; l=2

For example for 2.25C)
The problem gives you 3d. From this, you know that n=3 and that l= 2. The number of electrons would be 10 because ms=-2,-1,0,1,2; there are 5 orientations. You multiply 5 by 2 to get the number of electrons (ms- spins).


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