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Postby Stevin1H » Wed Oct 31, 2018 2:44 pm

Is the s orbital degenerate? Meaning, is the degeneracy of the s orbital equal to 0 or 1?

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Joined: Fri Sep 28, 2018 12:24 am

Re: Degeneracy

Postby Francis_Nguyen3D » Wed Oct 31, 2018 4:06 pm

the S orbital is not degenerate because its l value= 0 therefore making the m1 value=0. This makes the s orbital have 0 degeneracy.

Manya Bali 4E
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Re: Degeneracy

Postby Manya Bali 4E » Wed Oct 31, 2018 6:54 pm

Is degeneracy associated with a number? From what I understood, degenerate orbitals have the same energy level and become filled evenly. For example, when there are 3 2p orbitals in an atom, those orbitals all have the same energy level. s orbitals at different n levels, however, should have different energy levels and are thereby not degenerate, right?

Amy Dinh 1A
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Re: Degeneracy

Postby Amy Dinh 1A » Thu Nov 01, 2018 4:12 pm

The number of degenerate orbitals of an orbital is equal to twice angular momentum plus one (# degenerate orbitals = 2l + 1), so the s-orbital will have 1 degenerate orbital, the p-orbital will have 3, the d-orbital will have 5, and the f-orbital will have 7.

Emilee Hosking 1D
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Re: Degeneracy

Postby Emilee Hosking 1D » Tue Dec 04, 2018 6:56 pm

For an electron with quantum numbers n=3 and l=1, according to the formula (# of degenerate orbitals=2*l+1), the number of degenerate orbitals would be 2. However people have said that for a p orbital there are always 3 degenerates, so now I am confused. Is there any way to further explain this? In this case how many degenerate orbitals are there?

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