## Number of orbitals given quantum numbers

Katherine Fitzgerald 1A
Posts: 40
Joined: Fri Sep 29, 2017 7:05 am

### Number of orbitals given quantum numbers

How many orbitals can have the following quantum numbers in an atom: n=2,, l=1. ml=0?

The solutions manual says the answer is 4. Can someone walk me through why / how to get there?

Jeril Joseph 1B
Posts: 55
Joined: Mon Jun 17, 2019 7:23 am
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### Re: Number of orbitals given quantum numbers

Not sure if this will be a helpful explanation, but I'll try. So based on the principle quantum number, we know the element being discussed in the second row of the periodic table. This means that we're dealing with the s and p orbitals. So, we know that s has one orbital and p has 3 orbitals, equaling to 4. The magnetic numbers don't apply to a specific orbital since each magnetic number can be applied to each p-orbital. Hope this helps.

David Zhang 1B
Posts: 48
Joined: Mon Jun 17, 2019 7:23 am

### Re: Number of orbitals given quantum numbers

Orbital number is determined by the equation n^2. With n=2, you have both l=0 (s subshell) and l=1 (p subshell). For l=0, the s subshell only has 1 orbital (0). For l=1, the p subshell has 3 orbitals (+1,0,-1). Combined, there are 4 orbitals total.

Yasmin Olvera 1D
Posts: 29
Joined: Thu Feb 14, 2019 12:15 am

### Re: Number of orbitals given quantum numbers

I believe it is 4 orbitals since s-shell can have 1 and p-shell can have 3.

The d-shell has 5 and f shell has 7. But since we are only going to n=2 it would be 4.

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