HW 1D.23
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Jacey Yang 1F
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Re: HW 1D.23
Do you mean part C? When n=2, it can have values of 0 and 1 for l, which translate to one s-orbital and three p-orbitals respectively.
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Anne Tsai 1F
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Re: HW 1D.23
Because n=2, l can equal 0 or 1. If l=0, then ml=0. If l=1, then ml can equal -1, 0, or 1. In total there are 4 possible orbitals.
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Emil Velasco 1H
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Re: HW 1D.23
For part c, when n=2, it has 2s and 2p are valid orbitals
in which 2s contains 1 subshell orbital (mL=0) and 2p contains 3 subshell orbitals (mL=-1,0,+1)
in which 2s contains 1 subshell orbital (mL=0) and 2p contains 3 subshell orbitals (mL=-1,0,+1)
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britthanul234
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Re: HW 1D.23
l must equal 0 or 1 because n=2 in this case. If l=0 then ml=0, then ml=-1,0,1. Therefore, there are 4 possible orbitals.
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