l=4
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Re: l=4
I think he said in the lecture that in theory l could be equal to 4, but we don't have elements that are this high. So in the periodic table, there are no elements with l=4.
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Re: l=4
I believe in the lecture video he said that l can be any number up to n-1, depending on what n is. For example, if n is 6, l can be 1,2,3,4,5. However, there are only 4 orbitals. l=0 is the s orbital, 1 is p, 2 is d, and 3 is f.
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Re: l=4
It is possible it could be. However, you only have to worry about the l = 0,1,2,3 values for this class.
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Re: l=4
l could be 4, but Dr. Lavelle says that in this class we will only use up to l=3 since the subshell for l=3 is f, which is the highest orbital we'll use.
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Re: l=4
Based on the fact that we don't have elements with l = 4, I think it is best to keep l = 0, 1, 2, and 3.
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Re: l=4
Although theoretically l could be equal to 4, in this class I believe we only have to deal with l=0,1,2,3 which are s,p,d,f respectively
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Re: l=4
I believe that l=4 would be equivalent to higher orbitals, but in this class we are only dealing with 0,1,2,3.
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Re: l=4
I agree with the posts above, it is theoretically possible, but there are no elements in the periodic table that corresponds to l=4.
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Re: l=4
Thank you for posting! I had the same question and I had trouble wrapping my head around l. This forum definitely helped.
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