Which of the following increase when an electron in a lithium atom undergoes a transition from the 1s-orbital to a 2p-orbital?
(a) Energy of the electron. (b) Value of n. (c) Value of l. (d) Radius of the atom.
Which answers would be different for a hydrogen atom and in what way would they be different?
Textbook 1E #1
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 65
- Joined: Tue Oct 06, 2020 12:16 am
Re: Textbook 1E #1
a) energy of the electron would increase because it is in a higher energy level, meaning that they hold more potential energy to either come back down to the original potential energy.
c) But since it is entering a 2p orbital, that means that l=1 from l=0, the l number has changed
It is not b because the value of n does not change as the number of shells or energy levels are still the same
It might not be d because the lithium has not changed to an ion, and there will be no difference in the atomic radius.
c) But since it is entering a 2p orbital, that means that l=1 from l=0, the l number has changed
It is not b because the value of n does not change as the number of shells or energy levels are still the same
It might not be d because the lithium has not changed to an ion, and there will be no difference in the atomic radius.
-
- Posts: 55
- Joined: Wed Sep 30, 2020 9:38 pm
Re: Textbook 1E #1
Hi Jaylin!
I actually think all of them increase! Here's my explanation:
(a) electron energy will increase as they jump to a higher energy level and stray further from the nucleus.
(b) n also increases because the jump goes from n=1 to n=2
(c) l also increases because it goes from s orbital to p orbital.
(d) As the number of electrons increase, the radius will also increase as more shells are formed.
Hope this was helpful!
I actually think all of them increase! Here's my explanation:
(a) electron energy will increase as they jump to a higher energy level and stray further from the nucleus.
(b) n also increases because the jump goes from n=1 to n=2
(c) l also increases because it goes from s orbital to p orbital.
(d) As the number of electrons increase, the radius will also increase as more shells are formed.
Hope this was helpful!
-
- Posts: 50
- Joined: Wed Sep 30, 2020 9:42 pm
Re: Textbook 1E #1
Hi. A should increase as the electron needs energy to enter a higher energy level, thus the energy would be higher. The electron is going from 1s to 2p, and n, the principle quantum number, is the coefficient, so n goes from 1 to 2 - increasing. The value of l is larger, going from l = 0 in 1s to l = 1 for 2p. The radius is larger because an electron is now occupying a larger energy level, and generally the more energy an electron has the further it is from the nucleus.
The answers should be the same for hydrogen as well.
The answers should be the same for hydrogen as well.
-
- Posts: 62
- Joined: Wed Sep 30, 2020 9:59 pm
Re: Textbook 1E #1
Hey so here is what I got
A) so since it moving into a higher energy bracket 1s to 2p that means that the energy will increase.
B) we know that n is represented by the first number so 2p means n=2 not 1
C) so l is based off the n number so if n increased in part B then it will increase likewise in L.
D) lately the radius will increase because are adding more shells which is farther.
A) so since it moving into a higher energy bracket 1s to 2p that means that the energy will increase.
B) we know that n is represented by the first number so 2p means n=2 not 1
C) so l is based off the n number so if n increased in part B then it will increase likewise in L.
D) lately the radius will increase because are adding more shells which is farther.
Return to “Wave Functions and s-, p-, d-, f- Orbitals”
Who is online
Users browsing this forum: No registered users and 1 guest