Textbook 1E #1

Moderators: Chem_Mod, Chem_Admin

JaylinWangDis1L
Posts: 91
Joined: Wed Sep 30, 2020 10:09 pm

Textbook 1E #1

Postby JaylinWangDis1L » Sun Nov 01, 2020 6:16 pm

Which of the following increase when an electron in a lithium atom undergoes a transition from the 1s-orbital to a 2p-orbital?
(a) Energy of the electron. (b) Value of n. (c) Value of l. (d) Radius of the atom.
Which answers would be different for a hydrogen atom and in what way would they be different?

Tae Pasawat 2A
Posts: 65
Joined: Tue Oct 06, 2020 12:16 am

Re: Textbook 1E #1

Postby Tae Pasawat 2A » Sun Nov 01, 2020 7:12 pm

a) energy of the electron would increase because it is in a higher energy level, meaning that they hold more potential energy to either come back down to the original potential energy.

c) But since it is entering a 2p orbital, that means that l=1 from l=0, the l number has changed


It is not b because the value of n does not change as the number of shells or energy levels are still the same


It might not be d because the lithium has not changed to an ion, and there will be no difference in the atomic radius.

Melanie Lin 3E
Posts: 85
Joined: Wed Sep 30, 2020 9:38 pm

Re: Textbook 1E #1

Postby Melanie Lin 3E » Sun Nov 01, 2020 9:54 pm

Hi Jaylin!
I actually think all of them increase! Here's my explanation:
(a) electron energy will increase as they jump to a higher energy level and stray further from the nucleus.
(b) n also increases because the jump goes from n=1 to n=2
(c) l also increases because it goes from s orbital to p orbital.
(d) As the number of electrons increase, the radius will also increase as more shells are formed.
Hope this was helpful!

Manseej Khatri 2B
Posts: 76
Joined: Wed Sep 30, 2020 9:42 pm

Re: Textbook 1E #1

Postby Manseej Khatri 2B » Sun Nov 01, 2020 11:16 pm

Hi. A should increase as the electron needs energy to enter a higher energy level, thus the energy would be higher. The electron is going from 1s to 2p, and n, the principle quantum number, is the coefficient, so n goes from 1 to 2 - increasing. The value of l is larger, going from l = 0 in 1s to l = 1 for 2p. The radius is larger because an electron is now occupying a larger energy level, and generally the more energy an electron has the further it is from the nucleus.
The answers should be the same for hydrogen as well.

rhettfarmer-3H
Posts: 96
Joined: Wed Sep 30, 2020 9:59 pm

Re: Textbook 1E #1

Postby rhettfarmer-3H » Sun Nov 01, 2020 11:44 pm

Hey so here is what I got

A) so since it moving into a higher energy bracket 1s to 2p that means that the energy will increase.
B) we know that n is represented by the first number so 2p means n=2 not 1
C) so l is based off the n number so if n increased in part B then it will increase likewise in L.
D) lately the radius will increase because are adding more shells which is farther.


Return to “Wave Functions and s-, p-, d-, f- Orbitals”

Who is online

Users browsing this forum: No registered users and 1 guest