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Hi! So any orbital, as well as a d orbital, can only hold a max of 2 electrons and these electrons must have opposite spins. If you're a visual person, it helps to look at the periodic table. The d subshells are basically represented by the transition metals. Each row of transition metals has 10 elements, which are differentiated by a single electron when compared side to side (in the ground state). Thus, there are 10 electrons in the d subshell, with 2 per orbital, making 5 orbitals. Hope this helps!
Another good thing to know about d-orbitals is that they allow elements to produce expanded octets. Because of this, elements in the third row or below in the periodic table can have an expanded octet. This is because, for n = 3, d-orbitals can accommodate more electrons by participating in bonding with other atoms, producing an expanded octet.
Yes, you are right. S-,p-,d-, and f- orbitals can all hold up to 2 electrons in each orbital. Since there are 10 elements in the d-block of the periodic table, there are 10 electrons in the d-subshell. Since each orbital can hold 2 electrons maximum, there are 5 orbitals in total for this specific block.
Hi, so each orbital including d orbitals can hold up to max of 2 electrons due to the pauli exclusion principle. It happens to be 5 due to the ml being -2,-1,0,1,2 and the periodic table in the transition metal area can help visualize that.
Yeah you are correct! It doesn't matter if it's s-, p-, d-, or f- each orbital will have a max of 2 electrons. And if we look at the d-block of the periodic table, we can count that there are 10 electrons total in the d subshell, with a total of 5 orbitals. Hope this helps!
So basically, d orbitals are only present and empty in the elements from the 3rd period to beyond. This is especially useful to know for Lewis structures since that means the central atom can hold more than eight electrons forming something greater than an octet. The orbital itself has one node (where there are no electrons) and exists on the x,y, and z-axis in any orientation. For the d orbital, n=3, l=2, and me=-2,-1,0,1,2 (tells us the number of orbitals) so there are five with 10 electrons that can fill these orbitals in total (d^10).
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