Does the energy level in the orbitals go: s<p<d<f?
Thanks!
Energy level of orbitals
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Re: Energy level of orbitals
Just to add on, s<p<d<f is due to the effects of penetration and shielding (I.e. S has the lowest energy since it has no nodal planes). This follows the building-up/Aufbau's principle as well.
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Re: Energy level of orbitals
The orditals will fill f<d<p<s tho when your get to higher number of electrons/orbitals depending on the n
Re: Energy level of orbitals
Besides the general trend s<p<d<f, electrons enter 4s orbital before 3d because the 4s is initially Lower in energy. From Scandium (Sc) onwards, the 3d orbital becomes Lower than 4s.
We write 3d before 4s in configuration, like K [Ar]4s1, Ca [Ar]4s2 with no 3d orbitals
We write 3d before 4s in configuration, like K [Ar]4s1, Ca [Ar]4s2 with no 3d orbitals
Re: Energy level of orbitals
Yes it does go in that order and the electrons will be filled up accordingly, however there are some exceptions such as when 4s goes before 3d or the transition metals Cr and Cu are filled up differently in order to achieve symmetry and a lower energy state. Thus, s<p<d<f is correct for most atoms, but there are some exceptions to how electrons may be filled up.
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