order s, p, d, f... why?
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order s, p, d, f... why?
How come p orbitals have more energy than s orbitals in the same shell? Why is there a hierarchy within the same shell?
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Re: order s, p, d, f... why?
I believe this is partly due to the shape of the orbitals and the order they come in. S orbitals are spherical in nature, while the other orbitals have specific shapes which might make them higher in energy. In addition, there is electron to electron repulsion. The p orbital comes after the s orbital, so the electrons in the s orbital push against the p orbital, making it slightly higher.
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Re: order s, p, d, f... why?
The idea of electron - electron repulsion that the previous reply brought up is super important! When there is repulsion, more energy is required to maintain the system. This idea ties back into coulomb's law as well!
Re: order s, p, d, f... why?
How come p orbitals have more energy than s orbitals in the same shell? Why is there a hierarchy within the same shell?
Hi,
I guess that have to do with the shielding/electron-electron repulsion of inner shells.
s orbitals are closer to the nucleus than p orbitals. Therefore, repulsion between e- in s orbitals and p orbitals makes the effective nuclear charge on p smaller. I understand it as s electrons are pushing p electrons farther away from the nucleus. With less effective nuclear charge, the nucleus has less attraction force on p orbital electrons, allowing p to have more energy.
Hope this could help you!
Hi,
I guess that have to do with the shielding/electron-electron repulsion of inner shells.
s orbitals are closer to the nucleus than p orbitals. Therefore, repulsion between e- in s orbitals and p orbitals makes the effective nuclear charge on p smaller. I understand it as s electrons are pushing p electrons farther away from the nucleus. With less effective nuclear charge, the nucleus has less attraction force on p orbital electrons, allowing p to have more energy.
Hope this could help you!
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