wavelength range

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Sisam Bhattarai 2C
Posts: 131
Joined: Fri Sep 29, 2023 10:33 am

wavelength range

Postby Sisam Bhattarai 2C » Tue Oct 31, 2023 7:10 pm

Finding the number of spectral lines ( eg. n=5), I know you use n-1 to get it ( answ: 4 spectral lines). However, when finding its wavelength radiation, I am unsure what formula correlates with it and if it uses the lyman structure. Do I use 4 and 1 somehow to calculate it since those are the highest and lowest spectral lines when n+5. Thank you!

Ai-Tan La 1K
Posts: 103
Joined: Fri Sep 29, 2023 11:51 am
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Re: wavelength range

Postby Ai-Tan La 1K » Tue Oct 31, 2023 7:16 pm

To determine the wavelegnth range you would find the wavelength from the largest spectral from n=5 to n=1 with the equation v=R[1/n1^2-1/n2^2]. Then you would do the same for the smallest spectral line from n=5 to n=4. Then you would take these two wavelengths and find the difference between them to find the range.

Ashley 3A
Posts: 81
Joined: Fri Sep 29, 2023 11:35 am

Re: wavelength range

Postby Ashley 3A » Tue Oct 31, 2023 7:18 pm

You'll be using the Rydberg equation to find the frequency of n=5 to n=1 then to n=5 to n=4. Then convert these to wavelengths in meters and finally to nanometers.


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