6th Edition HW 2.29

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Alexa_Henrie_1I
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6th Edition HW 2.29

Postby Alexa_Henrie_1I » Sun Oct 21, 2018 3:39 pm

I don't really understand 2.29, the question asks to identify how many electrons can have the following quantum numbers in an atom. I don't know how to figure out the possible number of electrons that can have a specific quantum number. Can someone explain how to do this?

705170809
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Re: 6th Edition HW 2.29

Postby 705170809 » Sun Oct 21, 2018 4:13 pm

in a) n=2, l=1, that means that ml=-1,0,1, but there are also different spins in electrons, so since -1,0,1 (3 options), and there's a possibility of either electron being 1/2 or -1/2 (2 options), 3*2=6. So there are 6 different electrons that can have the following quantum numbers.
b) n=4, l=2, ml=-2 (1 options), then there's a possibility of either electron being 1/2 or -1/2 (2 options) 1*2=2. So there are 2 different electrons that can have the following quantum numbers.
And the same goes for the rest of 2.29

Alexa_Henrie_1I
Posts: 61
Joined: Fri Sep 29, 2017 7:03 am

Re: 6th Edition HW 2.29

Postby Alexa_Henrie_1I » Sun Oct 21, 2018 4:16 pm

Okay this makes sense. Thank you so much!


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