1D 13 Part A

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LBacker_2E
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1D 13 Part A

Postby LBacker_2E » Thu Oct 17, 2019 11:20 pm

I was wondering how you are supposed to solve part a of number 13, because I thought the question was just asking for how many possible values of l there could be with a principle quantum number of n=4. However, the answer says there are 7 possible values not 4, how do you arrive at this answer?

sarahwu3a
Posts: 50
Joined: Sat Aug 17, 2019 12:17 am

Re: 1D 13 Part A

Postby sarahwu3a » Fri Oct 18, 2019 2:02 am

The questions says when n=7, so l has the possible values of 0,1,2,3,4,5,6 which is 7 options.

Junxi Feng 3B
Posts: 52
Joined: Sat Sep 14, 2019 12:17 am

Re: 1D 13 Part A

Postby Junxi Feng 3B » Fri Oct 18, 2019 8:16 pm

By definition, l=0,1,....,n-1.
Since n=7, then l=0,1,2,3,4,5,6.
There are exactly 7 possible values for l.


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