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Anne Tsai 1F
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Joined: Thu Jul 25, 2019 12:15 am


Postby Anne Tsai 1F » Sun Oct 20, 2019 5:29 pm

For part c, the question is asking how many orbitals can have a quantum number of n=2. Does this mean to find the sum of all of the possible values for ml if l can equal 0 or 1?

Charisse Vu 1H
Posts: 101
Joined: Thu Jul 25, 2019 12:17 am

Re: 1D.23

Postby Charisse Vu 1H » Sun Oct 20, 2019 5:35 pm

Yes, your answer would be a summation of all the possible values for m and l given that n=2. If n=2, l must be 0 or 1 and m could therefore be -1, 0, or 1 if l=1. If l=0, then m could only be 0. The total number of orbitals then would be 4.

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