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Posted: Wed Oct 23, 2019 11:09 pm
What are the principal and orbital angular momentum quantum numbers for each of the following orbitals: (a) 6p; (b) 3d; (c) 2p; (d) 5f?
Can someone please explain how to solve this
Posted: Wed Oct 23, 2019 11:24 pm
The principle quantum number (n) is the number before the letter in the given orbital. To find the angular momentum quantum number (l) you use to following:
For part a, n=6 since the orbital is 6p, and l=1, since it is a p orbital.
For part b, n=3 since the orbital is 3d, and l=2, since it is a d orbital
Part C: n=2, l=1
Part D: n=5, l=3
Posted: Thu Oct 24, 2019 9:31 pm
The number is the principle quantum number, and the letter corresponds to the orbital angular momentum quantum number. If l=0 its s, l=1 its p, if l=2 its d, and if l=3 its f. From there you can find the answers for all of them.
Posted: Thu Oct 24, 2019 11:50 pm
also, the l value can always only be as high as the n value minus 1