Page 1 of 1


Posted: Wed Oct 23, 2019 11:09 pm
by Joanne Kang 3I
What are the principal and orbital angular momentum quantum numbers for each of the following orbitals: (a) 6p; (b) 3d; (c) 2p; (d) 5f?

Can someone please explain how to solve this

Re: 1D.15

Posted: Wed Oct 23, 2019 11:24 pm
by Ryan Chang 1C
The principle quantum number (n) is the number before the letter in the given orbital. To find the angular momentum quantum number (l) you use to following:

s; l=0
p; l=1
d; l=2
f; l=3

For part a, n=6 since the orbital is 6p, and l=1, since it is a p orbital.
For part b, n=3 since the orbital is 3d, and l=2, since it is a d orbital
Part C: n=2, l=1
Part D: n=5, l=3

Re: 1D.15

Posted: Thu Oct 24, 2019 9:31 pm
by LReedy_3C
The number is the principle quantum number, and the letter corresponds to the orbital angular momentum quantum number. If l=0 its s, l=1 its p, if l=2 its d, and if l=3 its f. From there you can find the answers for all of them.

Re: 1D.15

Posted: Thu Oct 24, 2019 11:50 pm
by Victor James 4I
also, the l value can always only be as high as the n value minus 1