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### 1D.15

Posted: **Wed Oct 23, 2019 11:09 pm**

by **Joanne Kang 3I**

What are the principal and orbital angular momentum quantum numbers for each of the following orbitals: (a) 6p; (b) 3d; (c) 2p; (d) 5f?

Can someone please explain how to solve this

### Re: 1D.15

Posted: **Wed Oct 23, 2019 11:24 pm**

by **Ryan Chang 1C**

The principle quantum number (n) is the number before the letter in the given orbital. To find the angular momentum quantum number (l) you use to following:

s; l=0

p; l=1

d; l=2

f; l=3

For part a, n=6 since the orbital is 6p, and l=1, since it is a p orbital.

For part b, n=3 since the orbital is 3d, and l=2, since it is a d orbital

Part C: n=2, l=1

Part D: n=5, l=3

### Re: 1D.15

Posted: **Thu Oct 24, 2019 9:31 pm**

by **LReedy_3C**

The number is the principle quantum number, and the letter corresponds to the orbital angular momentum quantum number. If l=0 its s, l=1 its p, if l=2 its d, and if l=3 its f. From there you can find the answers for all of them.

### Re: 1D.15

Posted: **Thu Oct 24, 2019 11:50 pm**

by **Victor James 4I**

also, the l value can always only be as high as the n value minus 1