1D.23

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Bryce Ramirez 1J
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Joined: Sat Aug 24, 2019 12:16 am

1D.23

Postby Bryce Ramirez 1J » Sun Oct 27, 2019 5:05 pm

When solving for orbitals and you are only given that n = 2, why is the answer? Solving for l would give you 1, which corresponds to the P orbital, giving you three. But the answer shows 4. Why is this?

JohnWalkiewicz2J
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Joined: Thu Jul 11, 2019 12:17 am
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Re: 1D.23

Postby JohnWalkiewicz2J » Sun Oct 27, 2019 5:10 pm

At n=2, l can equal 0 or 1, since there is an s and p subshell in that energy level.
2s = 1 orbital
2p = 3 orbitals.
If you add them up, you get a total of 4 orbitals for n=2.


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