when n=5 and l=4
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when n=5 and l=4
When the quantum number n is equal to five, l is then equal to 4. So in this case, what orbital does the 4th shell fall under then?
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Re: when n=5 and l=4
I don't believe that because n=5 that l has to automatically equal 4. l is based on the orbitals while n is the energy level. For example, if the configuration is [Kr] 5s^2 n=5 while l=0 as Strontium is in the s-orbital. Hope this helps!
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Re: when n=5 and l=4
n is the principle quantum number and represents the energy level an electron is located. l is the angular momentum of e and describes the shape of the orbital. n and l are not dependent on each other; you can have 4s, 4p, and 4d orbitals, where n=4 but l can be 1, 2, and 3 respectively.
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Re: when n=5 and l=4
General rule is that l is n-1. So the s orbital would be 0, p would be 1, and so on. When asked those types of problems on sapling, that is the easiest way to find the answer.
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Re: when n=5 and l=4
Although n=5 and the general rule is l=n-1, I don't think l automatically equals to 4. l can equal to 1,2,3 or 4 depending on the situation.
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Re: when n=5 and l=4
When the quantum number n=5, l can theoretically equal 4 but is not necessarily (or realistically 4). When n=5, l can be 0,1,2,3,4 since the values of l range from 0 to n-1. l=4 would also result in subshell g but as far as I know, no ground state elements have electrons in the g subshell.
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Re: when n=5 and l=4
n=5 and l=n-1, so l=4, it doesn't necessarily mean l=4 because l can also equal 3,2,1,0
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Re: when n=5 and l=4
for the last part of your question..."shell" refers to the principle quantum number, n, and "subshell" refers to the angular momentum, or the subshell/orbitals or s/p/d/f. So, the fourth shell would be when n=4, and the orbital/subshell can be l=0,1,2,3 for the "4th shell"
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Re: when n=5 and l=4
When n=5, l can has the possible values of 0,1,2,3,or 4 as in S,P,D,F, etc. orbitals. The formula to finding l is 0,1,2,...(n-1)
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Re: when n=5 and l=4
For the purposes of this class, I don't think we have to worry about the subshell when l=4. Just remember l relates to either s, p, d, or f which correspond to 0, 1,2, and 3 accordingly. Conceptually yes, when n=5, l is equal to everything up to n-1 but I don't think we can identify the subshell when l is greater than 3
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Re: when n=5 and l=4
L would not necessary equal 4, that is just the highest number l can be in this case. This is due to the different types of shells, which have different l levels.
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Re: when n=5 and l=4
If n is equal to 5, l can equal 0,1,2,3... (n-1), it does not necessarily have to be 4. When l is equal to 0=s, 1=p, 2=d, and 3=f.
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Re: when n=5 and l=4
When n=5 the general rule is that l=n-1 but that isn't always the case as l could potentially be 0,1,2,etc. For Sapling questions though, unless they give you a specific element, I would use the general rule for determination and l=4 corresponds to the letter g.
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Re: when n=5 and l=4
The professor said that we don't have to apply quantum numbers to "n" values greater than four for this class. Someone else should verify that, though.
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Re: when n=5 and l=4
I don't think we need to know the answer to this question since we usually are given values of l up to 3. l=0 corresponds to the s subshell, and l=1 corresponds to the p subshell. l=2 corresponds to the d subshell, and l=3 corresponds to the f subshell. Since there aren't any other subshells that we need to know besides s,p,d, and f, we won't need to know what orbitals correspond to l=4.
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