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At energy level n=2, an atom could have the s and p states. Therefore, there could be two atoms in the 2s state, and six atoms in the 2p state. In total, this atom could have eight electrons. This is represented on the periodic table, as Neon is the atom with the highest number of electrons (8) contained in the n=2 state.
Hi Chloe! To start this problem, I would reference the periodic table. The shell n=1 is represented by the first group. For n=1, 2 electrons can occupy this shell as seen by the 1s orbital that is represented by the 2 elements, H and He. For n=2, 8 electrons can occupy this shell because 2 electrons can occupy 2s orbital and 6 electrons can occupy the 2p orbital. Group 2 has 2 elements in the s-block and 6 elements in the p-block. Also, remember that there is 1 s-orbital shape and 3 p-orbital shapes, and 2 electrons can occupy each orbital. I hope that helps!
If you think of the atom as the classic Borh model (with circles of electrons) each n level corresponds to one circle. If it asks for n=2 then ignore all other circles, focus on what can exist in that one circle, which is 2s2p.
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