## Sapling #21

Rachel Kho Disc 2G
Posts: 60
Joined: Wed Sep 30, 2020 9:46 pm

### Sapling #21

The question is: how many electrons in an atom can have these sets of quantum numbers?

I was able to get the answers, but I'm having trouble with understanding why there are 14 electrons if n=5 and l=3. Would someone be able to help me out? Thanks!

SophiaJenny3I
Posts: 96
Joined: Wed Sep 30, 2020 9:56 pm
Been upvoted: 2 times

### Re: Sapling #21

Hi! So the l = 3 quantum number refers to the f orbital, which has 7 orbitals. Therefore, it could have 14 electrons, since there are two electrons per orbital. Hope this makes sense!

Marc Lubman 3B
Posts: 60
Joined: Wed Sep 30, 2020 10:00 pm
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### Re: Sapling #21

If l=3, then we're talking about the f-orbital, and there are seven different axial f suborbitals. Each of these suborbitals can hold two electrons, so the f orbital can hold a total of 14 electrons. An easy way to see this is that if you look at the f-block of the periodic table (lanthanides and actinides), you can see that it is a row of 14 elements, and as you go along it each element adds an electron to its f orbital.

Chanel Mao 3D
Posts: 62
Joined: Wed Sep 30, 2020 9:52 pm
Been upvoted: 1 time

### Re: Sapling #21

Hi!

Because n=5 and l=3, we are dealing with electrons in the 5F orbital. In this orbital, m can be -3,-2,-1,0,1,2, or 3 (basically 7 different orientations). Because there is a maximum of 2 electrons in each shell, there can be 14 electrons when n=5 and l=3. Hope this helps!

Callan Howard
Posts: 57
Joined: Wed Sep 30, 2020 10:00 pm

### Re: Sapling #21

Hi there,

looking at this table really helped me visualize the idea of electron affinity
https://sciencetrends.com/wp-content/up ... 00x381.png