1D. 21

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Kaitlin Joya 1I
Posts: 124
Joined: Fri Sep 24, 2021 7:21 am

1D. 21

Postby Kaitlin Joya 1I » Fri Oct 15, 2021 2:11 pm

Write the subshell notation (3d, for instance) and the number of orbitals having the following quantum numbers: a) n=5, l=2; b) n=1,l=0; c) n=6, l=3; d) n=2, l=1.

How do I find the number of orbitals for these? For a and b, I thought it was 5 orbitals and 1 orbitals because of n, but the same doesn't follow for c and d.

Mia Hansen 2I
Posts: 104
Joined: Fri Sep 24, 2021 6:33 am

Re: 1D. 21

Postby Mia Hansen 2I » Fri Oct 15, 2021 2:37 pm

Hi! The number of orbitals is related to the quantum number l, not n. s has 1 orbital, p has 3 orbitals, d has five orbitals, and f has seven orbitals.

Elena Chan 2L
Posts: 100
Joined: Fri Sep 24, 2021 5:25 am

Re: 1D. 21

Postby Elena Chan 2L » Fri Oct 15, 2021 3:21 pm

Hi!
As Mia said, the value of orbitals is calculated using the angular momentum quantum number, l, which is l=0 for s-orbital, l=1 for p-orbital, l=2 for d-orbital, and l=3 for f-orbital. So for A, l=2 which means it's the d-orbital or 5 orbitals; it is not related to the fact that the principle quantum number, n, is 5. This means A would be for the 5d quantum number. B, in turn, is 1 orbital for the s-orbital, C is 7 orbitals for the f-orbital, D is 3 orbitals for the p-orbital. Hope this helps!


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