## Chapter 2 Question 51 [ENDORSED]

Taylor_Yamane_2L
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### Chapter 2 Question 51

I am a little confused on exactly how to figure out how many unpaired electrons each element has. For example can someone please explain why Nickel has 2 unpaired electrons.

Thank you!!

Mizuno_Mikaela_1D
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### Re: Chapter 2 Question 51  [ENDORSED]

When finding the number of unpaired electrons predicted for the ground-state configuration of an atom, you are basically writing out the electron configuration and using Hund's rule to determine how many orbitals in the subshells are occupied with only one electron.

So for Nickel, the electron configuration is [Ar]3d^8,4s^2 which means that in the 3 d subshell, since the d subshell has 5 orbitals and there are 8 electrons for 3d, that means that there are two electrons in the first orbital, two electrons in the second orbital, two electrons in the third orbital and only one electron in the fourth and fifth orbital which means there are two unpaired electrons.

Sorry the explanation was probably a bit confusing but here is a video that explains it better:

Taylor_Yamane_2L
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### Re: Chapter 2 Question 51

Wow that explanation was so helpful and so was the video, thank you so much!