chapter 3 #13B

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Ariana Murillo 2O
Posts: 21
Joined: Tue Jul 19, 2016 3:00 am

chapter 3 #13B

Postby Ariana Murillo 2O » Mon Oct 24, 2016 10:55 pm

The question asks from which orbital will the electron be removed to form the ion of one greater positive charge for P3-. I thought it would be 3s as the second electron would move to the 3p5 orbital to make 3p6. However, the answer says 3p5. Why is that so?

Maggie Bui 1H
Posts: 35
Joined: Fri Jul 22, 2016 3:00 am
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Re: chapter 3 #13B

Postby Maggie Bui 1H » Tue Oct 25, 2016 6:47 am

Hi Ariana,

Electrons are removed from orbitals with the most energy first, so electrons from the 3p orbital will be removed before electrons from the 3s orbital.

Jasmine Cha 1A
Posts: 22
Joined: Wed Sep 21, 2016 2:59 pm

Re: chapter 3 #13B

Postby Jasmine Cha 1A » Tue Oct 25, 2016 9:56 am

It is because half-filled orbitals are more stable. This goes along with the electron configuration exceptions (i.e. Cr and Cu).


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