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chapter 3 #13B

Posted: Mon Oct 24, 2016 10:55 pm
by Ariana Murillo 2O
The question asks from which orbital will the electron be removed to form the ion of one greater positive charge for P3-. I thought it would be 3s as the second electron would move to the 3p5 orbital to make 3p6. However, the answer says 3p5. Why is that so?

Re: chapter 3 #13B

Posted: Tue Oct 25, 2016 6:47 am
by Maggie Bui 1H
Hi Ariana,

Electrons are removed from orbitals with the most energy first, so electrons from the 3p orbital will be removed before electrons from the 3s orbital.

Re: chapter 3 #13B

Posted: Tue Oct 25, 2016 9:56 am
by Jasmine Cha 1A
It is because half-filled orbitals are more stable. This goes along with the electron configuration exceptions (i.e. Cr and Cu).