## 3.5 b) [ENDORSED]

veneziaramirez 3I
Posts: 57
Joined: Fri Sep 29, 2017 7:07 am

### 3.5 b)

I still don't quite understand how we write electron configurations. The answer is [Xe] 4f^14 5d^10 6s^2 , and I understand it is in numerical order, but when we are solving it, do we solve it as [Xe] 6s^2 4f^14 5d^10 then rearrange it?

Salma Quintanilla 1J
Posts: 29
Joined: Wed Nov 23, 2016 3:02 am

### Re: 3.5 b)

If that is what is easiest for you. Just remember that in the answer, the n number should be in increasing order of energy levels. By doing this, it will be easier to write out the electron configurations for cations and anions.

DAllaf
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

### Re: 3.5 b)

In regards to solving it, it is just important to keep in mind that when electrons are taken away they are taken from the outermost shell. And in regards to writing out your answer, it is important to write them out in increasing energy levels. Hope this helps!

ramayyala1G
Posts: 31
Joined: Fri Feb 02, 2018 3:02 am

### Re: 3.5 b)

It may be easier for you to just count across the periodic table. That way you won't forget to put the the configuration in increasing order. Just out of curiosity, how are you solving it because it is kinda odd to get it all out of order and then put it in order.

Cate Guempel 1C
Posts: 3
Joined: Mon Apr 09, 2018 1:39 pm

### Re: 3.5 b)

I am also confused by this; I keep solving it out of order and getting mixed up.

Chem_Mod
Posts: 18400
Joined: Thu Aug 04, 2011 1:53 pm
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### Re: 3.5 b)  [ENDORSED]

When you fill the orbital diagrams, you can go across the periodic table, but you can also use the diagonal rule. I will also attach a photo here. This will mean that they fill out of order, to answer Ramay's question, because the first row of the d block will not be n=4, but instead n=3. The first row of the f block will not be n=6, but instead n=4. So yes, you should fill them out of order, but then put them back in order of the n value. Hope this helps!
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