f orbital

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Bree Perkins 1E
Posts: 34
Joined: Fri Apr 06, 2018 11:04 am

f orbital

Postby Bree Perkins 1E » Thu May 03, 2018 1:48 pm

Hi Everyone. I have a question about the f orbital. Since the f orbital begins at 57 (Lantharium), how would you write the electron configuration for that? Would it come after 6s? And if so, then what would 71 (Lutetium) be? Sorry if this question is confusing, I just want to make sure I understand how the table works!

Posts: 39
Joined: Fri Apr 06, 2018 11:05 am

Re: f orbital

Postby NatalieSDis1A » Thu May 03, 2018 3:11 pm

Lanthanum is part of the d block. The electron configuration would [Xe} 5d^1 6s^2. The electron configuration for Lutetium is [Xe] 4f^14 5d^1 6s^2. I believe the f block has a its own set of exceptions but we do not have to know them. We are only being tested on the first row of the d block.

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