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Yea! It is easier to remove the electrons that are on the outer shell. I think it helps if you start with the electron configuration of Cu first which from lecture we know it is one of the special exceptions as (Cu): [Ar] 3d^104s^1. From there you can see that the electron configuration for the ion Cu2+ would be 3d^9 because copper has lost 2 electrons, one is taken away from the s-orbital first and then you move on to take away another one from the d-orbital. Just remember that you always want to remove electrons from the outer shells first when you have a cation (positively charged ion). Hope this helps!
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