Hw problem 1E.7 part(c)

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Hw problem 1E.7 part(c)

Postby WYacob_2C » Fri Oct 18, 2019 12:21 pm

On the homework, problem 1.E.7 asks to "Determine whether each of the following electron configurations represents the ground state or an excited state of the atom given."
part (c) has Be as the element along with the electron configuration diagram. I'm confused as to why they placed one electron in the 2s orbital and one electron in the 2p orbital when the configuration of Be is 1s^2 2s^2. Would this make it in the excited state? If so, why? Thanks!

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Re: Hw problem 1E.7 part(c)

Postby TYun_1C » Fri Oct 18, 2019 12:25 pm

I'm not sure as to why they would place the electrons like that, but I would guess that it is in the ground state. Since theres still 4 electrons total, the atom would have a neutral +0 charge since the nucleus is +4 and the electrons are -4. Because of the neutral charge, I would assume it to be in its ground state. Hope this helps !

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