Homework Question 1E.9

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BeylemZ-1B
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Joined: Thu Jul 25, 2019 12:17 am

Homework Question 1E.9

Postby BeylemZ-1B » Mon Oct 21, 2019 4:05 pm

Can someone explain to me why the quantum numbers for 1E.9 part B are not possible? I understand part A and C, but something about B is really throwing me off.
Thanks so much!

105311039
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Joined: Fri Aug 02, 2019 12:16 am

Re: Homework Question 1E.9

Postby 105311039 » Mon Oct 21, 2019 4:17 pm

BeylemZ-4A wrote:Can someone explain to me why the quantum numbers for 1E.9 part B are not possible? I understand part A and C, but something about B is really throwing me off.
Thanks so much!

- For this question 1e.9 part B is not possible because of if the Ml value. Since l is equal to 0, Ml can only also equal 0 to make this possible. Ml only ranges from (-l to l). So in this case it can only be 0.

Chris Tai 1B
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Joined: Sat Aug 24, 2019 12:16 am

Re: Homework Question 1E.9

Postby Chris Tai 1B » Tue Oct 22, 2019 11:17 am

If the shell is 5s (due to the n=5 and l=0 values) then visually there cannot be any other orientations of the s orbitals. S orbitals are symmetric, as opposed to p d and f orbitals, which means they really only have one orientation. Because the value of ml reveals which orientation the orbital is in, ml can only be equivalent to 0, since the s orbital can't be oriented along any other axis or plane. Having an ml value other than 0 in this instance is impossible, given that no other orientations exist.

Rachel Yu 1G
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Joined: Fri Aug 09, 2019 12:15 am

Re: Homework Question 1E.9

Postby Rachel Yu 1G » Wed Oct 23, 2019 6:32 pm

Remember that ml values are dependent on l value. ml = -l to +l. Since l=0, the only possible value for ml is 0. This means that the ml value of -1 is not possible.


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