Hw problem 2A.13

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Hw problem 2A.13

Postby aphung1E » Wed Oct 30, 2019 1:13 am

Can someone show step by step how to do this problem?
2A.13 For each of the following ground-state atoms, predict the
type of orbital (1s, 2p, 3d, 4f, etc.) from which an electron will need
to be removed to form the 1 1 ions: (a) Zn; (b) Cl; (c) Al; (d) Cu

Michelle Le 1J
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Joined: Fri Aug 09, 2019 12:16 am

Re: Hw problem 2A.13

Postby Michelle Le 1J » Wed Oct 30, 2019 11:06 am

So first you would write the electron configuration of the atoms and then by looking at it, you would see which one is the last orbital in what you wrote and the electron in that orbital would be the one you need to remove. So for Zn, which is [Ar]3d104s2, the electron you would be removing is located in the 4s orbital.

Posts: 55
Joined: Sat Sep 07, 2019 12:17 am

Re: Hw problem 2A.13

Postby AChoudhry_1L » Thu Oct 31, 2019 6:51 pm

The way that I would approach this problem is by first writing out the ground state electron configurations. The electron would be removed from the last orbital and this is easier to see when you have the configuration written out.

Daniel Martinez 1k
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Joined: Wed Sep 18, 2019 12:16 am

Re: Hw problem 2A.13

Postby Daniel Martinez 1k » Thu Oct 31, 2019 7:29 pm

Make sure to remove the electrons from the highest energy orbital. For example Zn: [Ar] 3d^10 4s^2, the electrons would be removed from the 4s orbital since it is the highest energy orbital.

Yazmin Bocanegra 3L
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Joined: Thu Jul 25, 2019 12:17 am

Re: Hw problem 2A.13

Postby Yazmin Bocanegra 3L » Thu Oct 31, 2019 8:08 pm

First, you will have to write out the electron configurations for each of the elements in the question, then remove electrons from the highest energy orbital/outermost layer. For example, you will see that Zn has the highest energy orbital 4s^2, which is the outermost layer. You would remove electrons from here for each element. Hope this helps!

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