1 E.17

Moderators: Chem_Mod, Chem_Admin

Kaethe Zappacosta 2L
Posts: 106
Joined: Fri Sep 24, 2021 7:29 am

1 E.17

Postby Kaethe Zappacosta 2L » Sat Oct 16, 2021 7:26 pm

For each of the following ground-state atoms, predict the type of orbital (1s, 2p, 3d, 4f, etc.) from which an electron will be removed to form the +1 ion: (a) Ge; (b) Mn; (c) Ba; (d) Au

I do not understand this question. I thought the answer would just be wherever the last electron is. If Manganese's last electron is in the 3d orbital, why is the answer for part b 4s?

Gabriel McDonald 1J
Posts: 102
Joined: Fri Sep 24, 2021 6:54 am

Re: 1 E.17

Postby Gabriel McDonald 1J » Sat Oct 16, 2021 9:58 pm

It's 4s because when the 3d orbital starts to become filled, it is actually at a lower energy state than the 4s orbital. So the electron would get removed from 4s first. Dr. Lavelle showed us that the electron configuration for Scandium would be [Ar]3d14s2. Similarly, Manganese would be [Ar]3d54s2.


Return to “Electron Configurations for Multi-Electron Atoms”

Who is online

Users browsing this forum: No registered users and 4 guests