Question on 1E.5

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Anisha Chandra 1K
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Joined: Thu Jul 11, 2019 12:17 am

Question on 1E.5

Postby Anisha Chandra 1K » Sun Oct 27, 2019 10:17 am

For b, why are s electrons better at shielding than p electrons?

For d, how come effective nuclear charge is lower for p electrons than s electrons in the same shell? Doesn't higher effective nuclear charge = more protons, and p-orbital elements have higher atomic numbers?

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: Question on 1E.5

Postby Rodrigo2J » Sun Oct 27, 2019 10:36 am

B) s electrons tend to be better at shielding because they are closer to the nucleus.

D) effective nuclear charge is the net positive charge experienced by VALENCE electrons. Think about it this way, if there are more shielding electrons between the nucleus and the outer shell, the net positive charge on the valence electrons is less than if the outer shell had less shielding between the nucleus and valence electrons. Since s is closer to the nucleus and has less shielding, the net positive charge on the valence electrons is greater than in the p block which has more shielding.

Ada Chung 1C
Posts: 55
Joined: Sat Aug 17, 2019 12:15 am

Re: Question on 1E.5

Postby Ada Chung 1C » Sun Oct 27, 2019 10:43 am

b) To answer your question for b, s orbitals are more effective in shielding because remember that s orbitals are a sphere and have a higher probability of being closer to the nucleus whereas the p orbital has a lower probability (there is a node at the center). This indicates that effective nuclear charge is higher for electrons in s orbital.

d) For d, this builds off the reasoning in b that I gave. The greater the effective nuclear charge there will be less electron-electron repulsion and thus a smaller atom (you will find the electrons at a lower energy level). Remember that there is more electron-electron repulsion at higher orbitals. Hope this helps!


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