Achieve #28
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Achieve #28
How would you approach arranging the ions N3-, O2-, F-, Na+, Mg2+ from smallest to largest radius?
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Re: Achieve #28
When I did this problem I thought about it like this, the atoms with the largest radius will have the most electrons gained. even though all the atoms end up with the same electron configuration as Ne, the ones that had gained electrons have a larger radius than they would have had if they were to not have gained any electrons at all while those that lost electrons had a smaller radius at that time. Also with less electrons in the outer orbitals, the nucleus was able to pull the electrons closer to the center which constricts the radius as well.
Re: Achieve #28
Hi, since each ion has the same number of electrons, meaning that they are isoelectronic, you only have to focus on the charge. The most positive ion has the smallest radius while the most negative ion has the largest.
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Re: Achieve #28
Hi, so since they all have the same number of electrons, you have to consider the number of protons. Thus, since Ca has the most protons, its nucleus will have a tighter pull on the electrons and will have the smallest radius. On the other hand, since P has the least protons, it will have the largest radius.
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