## E.15 [ENDORSED]

Michael Lee 2I
Posts: 51
Joined: Fri Sep 29, 2017 7:05 am

### E.15

The molar mass of the metal hydroxide M(OH)2 is 74.10 g.mol^-1. What is the molar mass of the sulfide of this metal?

I was confused on finding the molar mass of the sulfide. Is there another number I am supposed to know to use to solve this problem?

Charlotte Shieh 1F
Posts: 9
Joined: Fri Sep 29, 2017 7:04 am

### Re: E.15

you find what the metal M is by subtracting the molar mass of (OH)2 from 74.10. you will find that M is calcium, so you just have to calculate the molar mass of CaS (which is the sulfide of the metal)

Kourtney Nham 1L
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

### Re: E.15

Going off what Charlotte said, it helps to look at the problem like 'M' is a variable!

Rachel Lu_dis1H
Posts: 66
Joined: Fri Sep 29, 2017 7:06 am
Been upvoted: 1 time

### Re: E.15

when they say that the molar mass of M(OH)2 is 74.10gmol-1 they're giving you two known elements O and H and one unknown M. To find what M is you subtract the molar mass of M(OH)2 by the molar mass of (OH)2. What you're left is the molar mass of M. You can then match that number with an element on the periodic table with that molar mass (Ca). Now that you know the unknown M which is Ca, you can find the molar mass of CaS which is your answer.

James Nguyen 3G
Posts: 19
Joined: Sat Jul 22, 2017 3:00 am

### Re: E.15

Are we expected to understand this concept for the upcoming test? As in sulfides, chlorides, etc.

DAllaf
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

### Re: E.15

Hey Michael,

You should begin by treating 'M' as an unknown variable. Then find the molar mass of (OH)2. Oxygen's molar mass is 15.99 g.mol^-1 and Hydrogen's molar mass is 1.008 g.mol^1. So multiply each by two since it has a subscript of two and then add them together to get a total molar mass of 34.00 g.mol^-1. Subtract this total from the given total molar mass of M(OH)2 which was 74.10 g.mol^-1. 74.10 - 34.00 = 40.1. Then by looking at the periodic table we see that Calcium has a molar mass of 40.08 g.mol^-1 which matches our remaining molar mass for variable 'M'. Thus we know 'M' is Calcium. In order to find the sulfide of Calcium you have to add Sulfur. So now you have CaS and the molar mass of this molecule is 72.14 g.mol^-1.

Hope this helps

nelms6678
Posts: 53
Joined: Fri Sep 29, 2017 7:07 am

### Re: E.15

An example from section "E"
What mass of NaHSO4 should you weigh out to obtain .20 mol NaHSO4?

How would you start this problem off? Im confused would this be Mass Percentage Comp.?

Anna Lapuos 3C
Posts: 10
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: E.15  [ENDORSED]

You use, m = nM.

The molar mass of NaHSO4 is 120.06 and you plug this value in for M, thus, the equation would look like this:

m = (0.20 mol)(120.06 g mol-1) = 24.01 g

NatalieSDis1A
Posts: 39
Joined: Fri Apr 06, 2018 11:05 am

### Re: E.15

This may be a bit obvious but I did not realize that M is not an element. It just stands for metal. I was confused about why people were saying to treat it as a variable but it is literally nothing more than a variable. And a sulfide is a compound with sulfur so it makes sense to combine the molar mass of the element we find and the molar mass of sulfur. Super obvious but it took me a couple minutes to realize this.

alexagreco1A
Posts: 34
Joined: Fri Apr 06, 2018 11:03 am

### Re: E.15

I had this question as well. I understand the explanation that 'M' is the variable, but would we have to know how to go about determining the sulfides for the test this week?