6th Edition Question E29b

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Netpheel Wang 4L
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

6th Edition Question E29b

Postby Netpheel Wang 4L » Tue Oct 02, 2018 11:06 pm

The solutions manual states that "Because there are 2 mol Cl per mole of compound, the number of moles will be twice the amount in part (a)"

I'm wondering why the number of moles is twice the amount in part (a) based on the amount of Cl moles.

Alma Carrera 3C
Posts: 33
Joined: Fri Apr 06, 2018 11:02 am

Re: 6th Edition Question E29b

Postby Alma Carrera 3C » Tue Oct 02, 2018 11:41 pm

It would be twice the amount in part (a) because in 1 mol of copper(II) chloride tetrahydrate there are 2 Cl atoms. Therefore, you multiply the number of moles from (a) times 2.


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