## 6th Edition Question G5

Netpheel Wang 4L
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

### 6th Edition Question G5

In the solution manual, it shows that $\frac{(2.5*10^-3 mol Na^+)(1molNa_{2}CO_{2})}{(.07967mol*L^-1)(2molNa^+)}$ but I don't understand why the term $1molNa_{2}CO_{2}$ is in the numerator and why $2molNa^+$ is in the denominator.

Atul Saha 3D
Posts: 30
Joined: Fri Sep 28, 2018 12:25 am

### Re: 6th Edition Question G5

Hey Netpheel,

Keep in mind that Na2CO2 would dissociate into its individual ions in an aqueous solution.
That specific equivalence in the dimension factor is meant to demonstrate that for every mole of Na2CO2, there are 2 moles of Na+ ions. You can figure this out by looking at the subscript on the Sodium (Na), which shows that every molecule of Sodium Carbonite requires requires 2 Na+ ions to form.

Much Joy,
Atul

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