## Formula M1V1=M2V2 [ENDORSED]

Jasmin Argueta 1K
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Joined: Fri Sep 28, 2018 12:16 am

### Formula M1V1=M2V2

The formula M1V1=M2V2 was not in the text, is that correct? For problem G13 it seems much easier to use that formula but shows another way in the text. We just know to use it when we are given say, 2 volumes and one molarity for instance?

Chem_Mod
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### Re: Formula M1V1=M2V2

That equation was used, but the solutions manual does not show it (the fact that the question says to solve without a calculator means the calculation could be done mentally).

Nicholas Carpo 1L
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Joined: Fri Sep 28, 2018 12:19 am

### Re: Formula M1V1=M2V2  [ENDORSED]

In G13, you still use that formula to some extent to solve the molarity of NH4NO3, although the calculation is not shown in the solution manual.

The equation M1V1=M2V2 becomes (0.20 M) (1.0 L) = (x) (1.0 + 3.0 L) which leads to the knowledge that the molarity of the diluted solution is 0.050 M.

You would then need to double this number as there are two N moles per mole of NH4NO3.

Rachel Dang 1H
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Joined: Fri Sep 28, 2018 12:17 am

### Re: Formula M1V1=M2V2

Yes we can use the that formula whenever we are given 3 of the 4 values or information to find those values.

Kayla Vo 1B
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

### Re: Formula M1V1=M2V2

Yes this equation can be used to solve problems like dilutions. Just be sure that your units always are converted to liters and mols/L (M) so that they cancel out during calculations.

SophiaKohlhoff4B
Posts: 30
Joined: Fri Sep 28, 2018 12:16 am

### Re: Formula M1V1=M2V2

This formula is especially useful in diluting stock solutions.